Question

The coordinate of base $BC$ of an isosceles triangle $ABC$ are given by $B(1,3)$ and $C(-2,7)$. Possible coordinates of the vertex $A$ can be:($\angle B=\angle C$)

• A. $(\frac{\sqrt{2}}{3},\frac{\sqrt{2}}{3})$
• B. $(\frac{2}{3},\frac{2}{3})$
• C. $(\frac{1}{3},\frac{1}{3})$
• D. None of these

Answer 1

The correct option is D None of these

$(x-1{)}^2+(y-3{)}^2=(x+2{)}^2+(y-7{)}^2{x}^2-2x+1+y^2-6y+9=x^2+4x+4+y^2-14y+496x-8y+43=0$

So none of the points satisfy the equation

so none of these.