The coordinates $(5, 2)$ and $(- 6, 2)$ are vertices of a hexagon.
Explain how to find the length of the segment formed by these endpoints.
How long is the segment?

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Solution

To find the distance between endpoints:
Let the point $A = (5, 2)$ and point $B = (- 6, 2)$ .
Use the distance formula and calculate the distance between given two points in below:
$\begin{array}{rcl} A B & = & \sqrt{{(x_{2} - x_{1})}^{2} + {(y_{2} - y_{1})}^{2}} [Distanceformula] \\ \Rightarrow & A B = \sqrt{{(- 6 - 5)}^{2} + {(2 - 2)}^{2}} [Substitutesallvalues] \\ \Rightarrow & A B = \sqrt{{(- 11)}^{2} + 0} [Simpifying] \\ \Rightarrow & A B = \sqrt{121} \\ ∴ A B & = & 11 \end{array}$
Hence, the segment is $11$ units long.

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△ A B C,

let

a, b

and

c

denote the lengths of sides opposite to vertices

A, B

and

C

respectively. If

a = 7, b = 3, c = 5

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equals

k,

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The coordinates 5,2 and -6,2 are vertices of a hexagon. Explain how to find the length of the segment formed by these endpoints. How long is the segment?

The coordinates $(5, 2)$ and $(- 6, 2)$ are vertices of a hexagon.
Explain how to find the length of the segment formed by these endpoints.
How long is the segment?