The coordinates of a point are atan(θ+α) and btan(θ+β), where θ is variable, then locus of the point is
A
Hyperbola
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B
Rectangular hyperbola
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C
Ellipse
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D
None of the above
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Solution
The correct option is A Hyperbola Given that, x=atan(θ+α) and y=btan(θ+β) or tan−1xa=θ+α....(i) and tan−1yb=θ+β....(ii) To get the required locus, we have to eliminate θ from Eqs. (i) and (ii). On subtracting Eq. (ii) from Eq. (i), we get tan−1(xa)−tan−1(yb)=α−β ⇒tan−1⎧⎪
⎪
⎪
⎪⎨⎪
⎪
⎪
⎪⎩(xa−yb)1+xa⋅yb⎫⎪
⎪
⎪
⎪⎬⎪
⎪
⎪
⎪⎭=α−β ⇒xa−yb1+xa⋅yb=tan(α−β) Simplifying, we get the required locus as xy+ab=(bx−ay)cot(α−β) which is a hyperbola.