CameraIcon
CameraIcon
SearchIcon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

The coordinates of a point on the line x12=y23=z3 at a distance 1 unit from the point (1,1,3) are

A
(32,74,543)
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
B
(32,114,34)
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
(12,54,34)
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
none of these.
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is C (32,74,543)
Let the point be
x=2t+1
y=3t+2
z=3t
Hence
P=(2t+1,3t+2,3t)
Q=(1,1,3)
Hence
PQ=1
PQ2=1
(2t+2)2+(3t+3)2+(3t+3)2=1
(t+1)2(4+9+3)=1
(t+1)2(16)=1
(4t+4)2=1
4t+4=±1
4t+4=1
t=54
Therefore
P=(32,74,534)

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Line in Three Dimensional Space
MATHEMATICS
Watch in App
Join BYJU'S Learning Program
CrossIcon