The coordinates of a point on the parabola y2=8x, whose focal distance is 4 units, is/are
A
(2,−4)
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
B
(12,−2)
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
(12,2)
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
(2,4)
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
Open in App
Solution
The correct options are A(2,−4) D(2,4) Let the point on the parabola y2=8x be P(x,y). Then its focal distance is SP=x+a. Here, a=2andSP=4. ∴4=x+2 ⇒x=2 ⇒y2=8×2 ⇒y=±4 Thus, the coordinates of the required points are (2±4).