The coordinates of a point on the parabola y2=8x, whose focal distance is 4 units, is/are
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Solution
Let the point on the parabola y2=8x be P(x,y).
Then its focal distance is SP=x+a.
Here, a=2andSP=4. ∴4=x+2 ⇒x=2 ⇒y2=8×2 ⇒y=±4
Thus, the coordinates of the required points are (2±4).