The coordinates of the end points of the latus rectum of parabola $x^{2} + 8 y = 0$ are $- ----- -$

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Solution

Equation of parabola : $x^{2} + 8 y = 0$
$\Rightarrow x^{2} = - 8 y$
$\Rightarrow a = 2$
Coordinate of end points of latus-rectum are
$L (2 a, - a) and L^{'} (- 2 a, - a)$
$\Rightarrow L = (4, - 2) and L^{'} = (- 4, - 2)$

Hence, the coordinate of the end points of the latus rectum of parabola $x^{2} + 8 y = 0$ are $(4, - 2) and (- 4, - 2)$ .

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