The coordinates of the focus of the parabola described parametrically by x=5t2+2,y=10t+4 are
A
(7,4)
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B
(3,4)
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C
(3,−4)
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D
(−7,4)
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Solution
The correct option is B(7,4) Given parametric curves are x=5t2+2,y=10t+4 or x−25=t2,y−410=t ⇒x−25=(y−410)2 ⇒(y−4)2=20(x−2) ⇒Y2=20X, where Y=y−4,X=x−2 ∴ Coordinates of focus are (5,0) ie, x−2=5, y−4=0 ⇒x=7, y=4 Hence, required coordinates are (7,4).