The coordinates of the focus of the parabola y2−x−2y+2=0 are
(54,1)
Given : The equation of the parabola is y2−x−2y+2=0
⇒ (y−1)2−1=(x−2)
⇒ (y−1)2=x−1
Let X=x−1,Y=y−1
∴ Y2=X
Comparing with Y2=4aX
a=14
Focus=(X=a,Y=0)=(X=14,Y=0)
=(x=14,y=1)=(x=54,y=1)
Hence,the focus is at (54,1)