The coordinates of the foot of perpendicular drawn from the point (2,4) on the line x+y=1, are
A
(12,32)
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B
(−12,32)
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C
(32,−12)
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D
(−12,−32)
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Solution
The correct option is B(−12,32) Equation of line ⊥(x+y=1) and passing through (2,4) will be y−4=(x−2) ⇒x−y+2=0⋯(1) So intersection of (1) with the given line will be foot of perpendicular of (2,4) Hence foot of perpendicular will be (−12,32)