The coordinates of the middle points of the sides of a triangle are $(3, 2),$ $(4, 3)$ and $(2, 2) .$ Then the coordinates of its centroid are

(3, 7 / 3)

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(3, 3)

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(4, 3)

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None of these

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Solution

The correct option is A $(3, 7 / 3)$
Coordinates of the mid points of the sides of a triangle are:

$(3, 2), (4, 3), (2, 2)$

Centroid $C = (\frac{x_{1} + x_{2} + x_{3}}{3}, \frac{y_{1} + y_{2} + y_{3}}{3})$

$= (\frac{3 + 4 + 2}{3}, \frac{2 + 3 + 2}{3})$

$∴ C = (3, \frac{7}{3})$

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The coordinates of the middle points of the sides of a triangle are (3,2), (4,3) and (2,2). Then the coordinates of its centroid are

The correct option is A (3,7/3)Coordinates of the mid points of the sides of a triangle are:(3,2),(4,3),(2,2)Centroid C=(x1+x2+x33,y1+y2+y33)=(3+4+23,2+3+23)∴C=(3,73)

The coordinates of the middle points of the sides of a triangle are $(3, 2),$ $(4, 3)$ and $(2, 2) .$ Then the coordinates of its centroid are

The correct option is A $(3, 7 / 3)$
Coordinates of the mid points of the sides of a triangle are:

$(3, 2), (4, 3), (2, 2)$

Centroid $C = (\frac{x_{1} + x_{2} + x_{3}}{3}, \frac{y_{1} + y_{2} + y_{3}}{3})$

$= (\frac{3 + 4 + 2}{3}, \frac{2 + 3 + 2}{3})$

$∴ C = (3, \frac{7}{3})$