The coordinates of the midpoint of a line segment joining $P (5, 7)$ and Q $(- 3, 3)$ are

(2, 4)

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(1, 5)

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(4, 2)

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(5, 2)

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Solution

The correct option is A $(1, 5)$
Let two points $(x_{1}, y_{1})$ and $(x_{2}, y_{2})$ then midpoint of line joining these two points is given by $(\frac{x_{1} + x_{2}}{2}, \frac{y_{1} + y_{2}}{2})$
Given $P (5, 7)$ and $Q (- 3, 3)$

Mid of $P Q$ will be $(\frac{5 - 3}{2}, \frac{7 + 3}{2})$
$= (\frac{2}{2}, \frac{10}{2}) = (1, 5)$

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The coordinates of the midpoint of a line segment joining P(5,7) and Q (−3,3) are

The correct option is A (1,5)Let two points (x1,y1) and (x2,y2) then midpoint of line joining these two points is given by (x1+x22,y1+y22)Given P(5,7) and Q(−3,3)Mid of PQ will be (5−32,7+32) =(22,102)=(1,5)

The coordinates of the midpoint of a line segment joining $P (5, 7)$ and Q $(- 3, 3)$ are