The coordinates of the point of contact of the tangent to the parabola y2=16x, which is perpendicular to the line 2x−y+5=0 are
(16, -16)
y2=16x .........(1)4a=16⇒a=42x−y+5=0 .......(2)
A line is perpendicular to the line (2) is
x+2y+λ=0 ......(3)⇒Slope, m=−12
Slope of the tangent to a parabola at (at2,2at) is 1t. Hence, a line having slope m intersects the parabola at (am2,2am)
Line (3) touches the parabola (1). So, the coordinates of the point of contact is
⇒P(am2,2am)=(16,−16)