The coordinates of the point which divides the line segment joining (4, –3) and (9, 7) in the ratio 3 : 2 externally is .

(19, 27)

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(7, 3)

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(35, 15)

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(\frac{19}{5}, \frac{27}{5})

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Solution

The correct option is A (19, 27)
Let A(4, -3), B(9, 7) be the points
and C divides AB externally in the
ratio 3 : 2.

$So, by using section formula for external division between two points A (x_{1}, y_{1}) and B (x_{2}, y_{2}), the point of division has the coordinates (\frac{m x_{2} - n x_{1}}{m - n}, \frac{m y_{2} - n y_{1}}{m - n}) ∴ C o o r d i n a t e s o f C w i l l b e (\frac{3 \times 9 - 2 \times 4}{3 - 2}, \frac{3 \times 7 - 2 \times (- 3)}{3 - 2}) = (19, 27)$

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Similar questions

Which of the following statments are correct?

1. The coordinates of the point which divides the line segment joining the points

$(1, - 2, 3)$ and $(3, 4, - 5)$ internally in the ratio $2 : 3$ is $(- 3, - 14, 19)$ .

2. The coordinates of the point which divides the line segment joining the points

$(1, - 2, 3)$ and $(3, 4, - 5)$ externally in the ratio $2 : 3$ is $(\frac{9}{5}, \frac{2}{5}, \frac{- 1}{5})$ .

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