The coordinates of two points P and Q are (2,3) and (3,2) respectively. Circles are described on OP and OQ as diameters; O being the origin, then length of the common chord is
A
√2
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B
√13
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C
5√2
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D
None of these
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Solution
The correct option is C5√2 Equation of circles are x2+y2−2x−3y=0 and x2+y2−3x−2y=0. Equation of the common chord is y=x, for the points os intersection 2x2−5x=0⇒x=0,52 Length of the chord =√(52)2+(52)2=5√2