Question

The coordination number and oxidation number of M in the complex.$\left[M\right(N{H}_3{)}_{5}S{O}_4]Cl$ are :

• A. 10,3
• B. 6,4
• C. 2,4
• D. 6,3

Answer 1

The correct option is D 6,3

The given complex compound is $\left[M\right(N{H}_3{)}_{5}S{O}_4]Cl$
$N{H}_3,S{O}_4$ are monodentate ligands so the co-ordination number of M is 6.

Let 'x' be the oxidation number of M.
Charge of $C{l}^{-}=-1$
Charge of $S{O}_4^{2-}=-2$
Charge of $N{H}_3=0$
Charge on complex ion = oxidation number of metal ion + Charge on ligands
$0=x+(-2)+(-1)$
$\Rightarrow x=+3$
The oxidation number of $M$ in $\left[M\right(N{H}_3{)}_{5}S{O}_4]Cl$ is +3. Hence, option (d) is correct.