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Byju's Answer
Standard XII
Chemistry
Coordination Complexes
The coordinat...
Question
The coordination number and oxidation number of the central metal ion in the complex
[
P
t
(
e
n
)
2
]
+
2
is:
A
C.N.
=
2
, O.N.
=
+
2
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B
C.N.
=
6
, O.N.
=
+
4
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C
C.N.
=
4
, O.N.
=
+
4
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D
C.N.
=
4
, O.N.
=
+
2
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Solution
The correct option is
C
C.N.
=
4
, O.N.
=
+
2
Ethylenediamine which is bidentate ligand is of two in number hence 2X2 =4
Hence co-ordination number of Platinum will be 4
Oxidation state = [x + 2 (0)] = 2+
x =+2
Thus, coordination number is 4 and oxidation number is +2
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Similar questions
Q.
A
B
−
4
+
C
+
2
→
C
+
3
+
A
+
2
If the Oxidation number of B is -2. Choose the true statement for the above change -
Q.
In
N
a
2
S
2
O
2
, the two S – atoms have O.N. as :-
Q.
What is the oxidation number of
S
in
H
2
S
4
O
6
.
Q.
Compounds
O.N.
(A)
K
M
n
∗
O
4
(1)
+4
(B)
N
i
∗
(
C
O
)
4
(2)
+7
(C)
[
P
t
∗
(
N
H
3
)
C
l
2
]
C
l
2
(3)
0
(D)
N
a
2
O
∗
2
(4)
-1
The correct code for the O.N. of asterisked atom would be:
Q.
Assertion :Carbon has coordination number
(
C
.
N
.
)
of four while other elements of this group have
C
.
N
.
of six. Reason: Due to available
d
-orbital in which
(
n
−
1
)
p
electrons.can be excited to make
C
.
N
.
of six. Carbon lacks
d
−
orbital.
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