Question

The coordination number and oxidation number of the central metal ion in the complex $\left[Pt\right(en{)}_2{]}^{+2}$ is:

• A. C.N. $=2$, O.N. $=+2$
• B. C.N. $=6$, O.N. $=+4$
• C. C.N. $=4$, O.N. $=+4$
• D. C.N. $=4$, O.N. $=+2$

Answer 1

Answer: (D)

C.N. $=4$, O.N. $=+2$

Ethylenediamine which is bidentate ligand is of two in number hence 2X2 =4

Hence co-ordination number of Platinum will be 4

Oxidation state = [x + 2 (0)] = 2+

x =+2

Thus, coordination number is 4 and oxidation number is +2