Question

The COP of a Carnot heat pump operating between $6^{\circ }Cand{37}^{\circ }C$ is

Answer 1

Given data:



$T_2=6^{\circ }C=(6+273)K$
= 279 K

$T_1={37}^{\circ }C=(37+273)K$
=310 K

$(COP{)}_{HP}=\frac{T_1}{T_1-T_2}=\frac{310}{310-279}$
= 10