The correct arrangement for the ions in the increasing order of their radii is:

{C a}^{+ 2}, K^{+}, S^{- 2}

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{C l}^{-}, F^{-}, S^{- 2}

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{N a}^{+}, {C l}^{-}, {C a}^{+ 2}

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{N a}^{+}, {A l}^{+ 3}, {B e}^{+ 2}

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Solution

The correct option is A ${C a}^{+ 2}, K^{+}, S^{- 2}$
Anions are bigger than cation and as charge increases size decreases. Hence order is $C a^{2 +} < K^{+} < S^{2 -}$ .

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