The correct arrangement of following acids of phosphorus in the increasing order of oxidation state of phosphorous is:

hypophosphorous acid < orthophosphorous acid < pyrophosphoric acid

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hypophoshporous acid < pyrophosphoric acid < orthophosphorous acid

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pyrophosphoric acid < hypophosphrous acid < orthophosphorous acid

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pyrophosphoric aicd < orthophosphorous acid < hypophosphorous acid

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Solution

The correct option is A hypophosphorous acid < orthophosphorous acid < pyrophosphoric acid
_{Hypophosphorous: $H_{3} P O_{2}$}
Oxidation state of $P = + 1.$ _{Orthophosphorous acid: $H_{3} P O_{3}$
Oxidation state of $P = + 3$}
Pyrophosphoric acid: $H_{4} P_{2} O_{7}$
Oxidation state of $P = + 5,$

The order is as follows:

$Hypophosphorous acid < Orthophosphorous acid < Pyrophosphoric acid$

Hence, option $A$ is correct.

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P_{2} O_{5}

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\begin{matrix} List - I (Name of oxo acid) & List - II (Oxidation state of P) (a) & Hypophosphorous acid & (i) & + 5 (b) & Orthophosphoric acid & (i i) & + 4 (c) & Hypophosphoric acid & (i i i) & + 3 (d) & Orthophosphorous acid & (i v) & + 2 (v) & + 1 \end{matrix}

H_{3} P O_{2}

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