The correct arrangement of the elements in the order of decreasing ionization energies is:

Na>Mg>Al

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Mg>Na>Al

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Al>Mg>Na

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Mg>Al>Na

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Solution

The correct option is D Mg>Al>Na
The general trend is forionization energy to increase moving from left to right across an element period. Moving left to right across a period, atomic radius decreases, so electrons are more attracted to the (closer) nucleus.
According to the trend the order of I.E will be $A l > M g > N a$
But,its outer electron is in the 3p-orbital which is slightly further from the nucleus and is shielded by the 3s-orbital and is therefore requires less energy to remove than the magnesium's outer electron which is closer and not as shielded.
Hence the order is $M g > A l > N a$

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. if true enter 1 ,else enter 0.

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