The correct ascending order of C-O bond lengths in CO - CO 32- and CO 2 is -A- CO 32- CO 2- COB- CO 2- CO 32- COC- CO - CO 32- CO 2D- CO - CO 2- CO 32

The correct option is D CO CO_2 CO_3^2– nbsp; nbsp;Bond length α 1Bond order Bond order of CO = 3 (as its isoelectronic with N_2) Bond order = Tot ...

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Byju's Answer

Standard XII

Chemistry

Nomenclature of Unsaturated Hydrocarbons

The correct a...

Question

The correct ascending order of C-O bond
lengths in $C O, C O_{3}^{2 -} and C O_{2}$ is :

C O_{3}^{2 -} < C O_{2} < C O

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C O_{2} < C O_{3}^{2 -} < C O

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C O < C O_{3}^{2 -} < C O_{2}

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C O < C O_{2} < C O_{3}^{2 -}

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Solution

The correct option is D $C O < C O_{2} < C O_{3}^{2 -}$
$B o n d l e n g t h α \frac{1}{B o n d o r d e r}$

Bond order of $C O$ = 3 (as its isoelectronic with $N_{2}$ )
$B o n d o r d e r = \frac{T o t a l n u m b e r o f b o n d s i n a l l p o s s i b l e s t r u c t u r e s}{N u m b e r o f r e s o n a t i n g s t r u c t u r e s}$ [If there is resonance]

$B o n d o r d e r o f C O_{2} = \frac{4}{2} = 2$
$B o n d o r d e r o f C O_{3}^{2 -} = \frac{4}{3} = 1.33$
So, order of $C - O$ bond lengths is $C O < C O_{2} < C O_{3}^{2 -}$

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The correct ascending order of C-O bond lengths in CO, CO2–3 and CO2 is :

The correct ascending order of C-O bond
lengths in $C O, C O_{3}^{2 -} and C O_{2}$ is :