The correct basicity order of the following lanthanide ions is:

L a^{3 +} > L u^{3 +} > C e^{3 +} > E u^{3 +}

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C e^{3 +} > L u^{3 +} > L a^{3 +} > E u^{3 +}

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L u^{3 +} > C e^{3 +} > E u^{3 +} > L a^{3 +}

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L a^{3 +} > C e^{3 +} > E u^{3 +} > L u^{3 +}

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Solution

The correct option is C $L a^{3 +} > C e^{3 +} > E u^{3 +} > L u^{3 +}$
The correct basicity order of the following lanthanide ions is $L a^{3 +} > C e^{3 +} > E u^{3 +} > L u^{3 +}$ .

Due to lanthanoid contraction, with an increase in the atomic number, the basicity decreases from $L a^{3 +}$ to $L u^{3 +}$ .

Hence, option $D$ is correct.

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Similar questions

Y^{3 +}, E u^{3 +}, L a^{3 +}, L u^{3 +}

The correct order of ionic radius for $Y^{3 +}, L a^{3 +}, E u^{3 +}$ and $L u^{3 +}$ is:

Y^{3 +}, L a^{3 +}, E u^{3 +}

L u^{3 +}

C e^{3 +}, L a^{3 +}, P m^{3 +}

Y b^{3 +}

C e, L a, P m

Y b

+ 3

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