The correct decreasing order of acidic strength is:

N O_{2} C H_{2} C O O H > N C C H_{2} C O O H > F C H_{2} C O O H > C l C H_{2} C O O H

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F C H_{2} C O O H > N C C H_{2} C O O H > N O_{2} C O O H > C l C H_{2} C O O H

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N O_{2} C H_{2} C O O H > F C H_{2} C O O H > N C C H_{2} C O O H > C l C H_{2} C O O H

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N C C H_{2} C O O H > N O_{2} C H_{2} C O O H > F C H_{2} C O O H > C l C H_{2} C O O H

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Solution

The correct option is A $N O_{2} C H_{2} C O O H > N C C H_{2} C O O H > F C H_{2} C O O H > C l C H_{2} C O O H$
Acidic strength increases as the stability of the conjugate base increases.
Considering the strength of the given electron withdrawing group in the acids, acidic strength follows the order:
$N O_{2} C H_{2} C O O H > N C C H_{2} C O O H > F C H_{2} C O O H > C l C H_{2} C O O H$

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