The correct decreasing order of magnetic (spin only formula) of the compound is:
(A) $[C o (S C N)_{6}]^{3 -}$
(B) $[N i (C O)_{4}]$
(C) $[C u (N H_{3})_{4}]^{2 +}$
(D) $[F e (H_{2} O)_{5} N O]^{2 +}$

D > A > C > B

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D > C > A > B

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A > D > C > B

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A > C > D > B

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Solution

The correct option is A $D > A > C > B$
$D > A > C > B$ .
(A) option is correct. because the (D) has lowest atomic no and B has highest atomic no

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Similar questions

The correct order of decreasing boiling points of CH₃CONH₂ (A) CH₃COCl (B) CH₃COOH (C) and (CH₃CO)₂O (D) is:

H B r

C H_{3} C | O | - O^{-}

C H_{3} O^{-}

C N^{-}

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