The correct decreasing order of ${S N}^{1}$ reactivity of the following is :
$I . P h {C H}_{2} X$ $I I . {C H}_{2} = C H {C H}_{2} X$
$I I I . {M e}_{2} C H X$ $I V . C_{2} H_{5} X$

(I) > (I I) > (I I I) > (I V)

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(I V) > (I I I) > (I I) > (I)

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(I I) > (I) > (I I I) > (I V)

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(I V) > (I I I) > (I) > (I I)

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Solution

The correct option is A $(I) > (I I) > (I I I) > (I V)$
In the $S_{N} 1$ reaction carbocation intermediate is formed.

More stable the carbocation more is the reactivity.

Stability order for carbocation is:

Benzyl > Allyl carbocation > secondary carbocation > primary

The correct decreasing order of $S N^{1}$ reactivity is;

$I . P h C H_{2} X > I I . C H_{2} = C H C H_{2} X > I I I . M e_{2} C H X > I V . C_{2} H_{5} X$

Option A is correct.

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(c) IV > V > III > II > I
(d) V > IV > III > II > I

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The correct decreasing order of SN1 reactivity of the following is :I. PhCH2X II. CH2=CHCH2XIII. Me2CHX IV. C2H5X

The correct decreasing order of ${S N}^{1}$ reactivity of the following is :
$I . P h {C H}_{2} X$ $I I . {C H}_{2} = C H {C H}_{2} X$
$I I I . {M e}_{2} C H X$ $I V . C_{2} H_{5} X$