The correct decreasing order of the ionic radii of the given isoelectronic species is

दी गई समइलेक्ट्रॉनीय स्पीशीज की आयनिक त्रिज्याओं का सही घटता क्रम है

Ca²⁺ > K⁺ > Cl^– > S^2–

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S^2– > Cl^– > K⁺ > Ca²⁺

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Cl^– > Ca²⁺ > K⁺ > S^2–

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Ca²⁺ > Cl^– > K⁺ > S^2–

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Solution

The correct option is B S^2– > Cl^– > K⁺ > Ca²⁺
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The correct order of decreasing ionic radii among the following isoelectronic species is:

The correct order of the decreasing ionic radii among the following isoelectronic species is [CBSE A1PMT 2010]

CH \equiv C - C H_{2} - COOH I; C H_{2} = CH - C H_{2} COOH II; C H_{3} C H_{2} C H_{2} COOH III

H_{2}^{+}, H_{2}

O_{2}^{+}

H_{2} S, N H_{3}, B F_{3}

S i H_{4}

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