The correct decreasing order of van der waals constant $^{'} a^{'}$ is:
$S O_{2}$ $C l_{2}$ $N H_{3}$ HCl
I II III IV

I > I I > I I I > I V

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I V > I I I > I I > I

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I I I > I > I I > I V

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I V > I I > I > I I I

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Solution

The correct option is A $I > I I > I I I > I V$
Compound Underwall constant (a)
$H C l$ $3.7$
${S O}_{2}$ $6.865$
${N H}_{3}$ $4.225$
${C l}_{2}$ $6.343$
Order ${S O}_{2} > {C l}_{2} > {N H}_{3} > {C l}_{2}$
Ans :- Option A

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Similar questions

Q. The decreasing order of

- I

effect for the given groups is:
(i)

- C N

(ii)

- N O_{2}

(iii)

- N H_{2}

(iv)

- F

Order of decreasing acidity of

$(i) H C O O H (i i) C H_{3} C O O H (i i i) C l_{2} C H C O O H (i v) C F_{3} C O O H i s$

Q. The correct decreasing order of -I effect of the given groups will be:

(i) C N (i i) N O_{2} (i i i) N H_{2} (i v) F

Order of decreasing acidity of the following is

(I) HCOOH

(II) ${C H}_{3} C O O H$

(III) ${C l}_{2} C H C O O H$

(IV) ${C F}_{3} C O O H$

Mark the correct order of decreasing acid strength of the following compounds.

(a) V > IV > II > I > III
(b) II > IV > I > III > V
(c) IV > V > III > II > I
(d) V > IV > III > II > I

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The correct decreasing order of van der waals constant ′a′ is:SO2Cl2NH3HClIIIIIIIV

The correct option is A I>II>III>IVCompound Underwall constant (a) HCl 3.7 SO2 6.865 NH3 4.225 Cl2 6.343Order SO2>Cl2>NH3>Cl2Ans :- Option A

The correct decreasing order of van der waals constant $^{'} a^{'}$ is:
$S O_{2}$ $C l_{2}$ $N H_{3}$ HCl
I II III IV

The correct option is A $I > I I > I I I > I V$
Compound Underwall constant (a)
$H C l$ $3.7$
${S O}_{2}$ $6.865$
${N H}_{3}$ $4.225$
${C l}_{2}$ $6.343$
Order ${S O}_{2} > {C l}_{2} > {N H}_{3} > {C l}_{2}$
Ans :- Option A