The correct description of the fischer projection of glyceraldehyde given below, in terms of $D$ & $L; R$ & $S$ and $d$ & $l$ , respectively, is:

D, R, d

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D, R, l

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D, S, d

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D, S, l

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Solution

The correct option is A $D, R, d$
anti clockwise rotation $⟹ S$
But $H$ present towards view reverse the configuration i.e. $R .$
Since $^{-} O H$ is present towards right side therefore it is $D$ isomer.
$⟹ R \approx d (+)$ (dextrorotatory)
Therefore, configurations are $D, R, d$ .

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‘ l^{'}

and ‘m’ are respectively azimuthal and magnetic quantum numbers.

\begin{matrix} Column-I & Column-II (a) & Number of values of^{'} l^{'} for an energy level & (p) & 0, 1, 2..... (n - 1) (b) & Actual values of^{'} l^{'} for a particular type of & (q) & + ‘ l^{'} to - ‘ l^{'} through zero orbital (c) & Number of values of 'm' for^{'} l^{'} = 2 & (r) & 5 (d) & Actual values of 'm' for a particular type of & (s) & n orbital \end{matrix}

Q. The Fischer presentation of D-glucose is given below

The correct structure(s) of

β - L - g l u c o p y r a n o s e i s (a r e)

\begin{matrix} Column-I & Column-II (a) & I C l & (p) & Linear (b) & B r F_{2}^{+} & (q) & Angular (c) & C l F_{4}^{-} & (r) & Tetrahedral (d) & A l C l_{4}^{-} & (s) & Square planar \end{matrix}

Column -I	Column-II
A. $2 s$	(P) $n = 4, l = 2, m = 0$
B. $2 p_{z}$	(Q) $n = 4, l = 2, m = - 2 o r + 2$
C. $4 d_{x^{2} - y^{2}}$	(R) $n = 2, l = 1, m = 0$
D. $4 d_{z}^{2}$	(S) $n = 2, l = 0, m = 0$

Match the column -I with column -II

$\begin{matrix} Column I & Column II (a) & a r g (\frac{z + 1}{z - 1}) = \frac{π}{4} & (p) & Parabola (b) & z = \frac{3 i - 1}{2 + i t} (t ϵ R) & (q) & Part of a circle (c) & a r g z = \frac{π}{4} & (r) & Full circle (d) & z = t + i t^{2} (t ϵ R) & (s) & Line \end{matrix}$

Which of the following is correct?

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The correct description of the fischer projection of glyceraldehyde given below, in terms of D & L;R & S and d & l, respectively, is:

The correct option is A D,R,danti clockwise rotation ⟹SBut H present towards view reverse the configuration i.e. R.Since −OH is present towards right side therefore it is D isomer.⟹R≈d(+) (dextrorotatory)Therefore, configurations are D,R,d.

The correct description of the fischer projection of glyceraldehyde given below, in terms of $D$ & $L; R$ & $S$ and $d$ & $l$ , respectively, is:

The correct option is A $D, R, d$
anti clockwise rotation $⟹ S$
But $H$ present towards view reverse the configuration i.e. $R .$
Since $^{-} O H$ is present towards right side therefore it is $D$ isomer.
$⟹ R \approx d (+)$ (dextrorotatory)
Therefore, configurations are $D, R, d$ .