The correct electron-dot formulation for hydrogen cyanide shows:

1 C-H bond, 1 C=N bond, 1 lone pair of electrons on the C atom and 1 lone pair of electrons on the N atom.

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2 double bonds and two lone pairs of electrons on the N atom.

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1 triple bond between C and N, 1 N-H bond and 2 lone pairs of electrons on the C atom.

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1 C-H bond, 1 C-N bond, 2 lone pairs of electrons on the C atom and 3 lone pairs of electrons on the N atom.

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1 triple bond between C and N, 1 C-H bond and 1 lone pair of electrons on the N atom.

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Solution

The correct option is E 1 triple bond between C and N, 1 C-H bond and 1 lone pair of electrons on the N atom.
The correct electron-dot formulation for hydrogen cyanide shows 1 triple bond between C and N, 1 C-H bond and 1 lone pair of electrons on the N atom.
$H - C \equiv N :$
In the above formula, all the atoms have completed their octets.

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