The correct electronic configuration of an alkaline earth metals can be:

[Ne]3s² 3p²

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[Ar]3d¹⁰ 4s²

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[Ar] 4s²

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[Ar]3d¹⁰ 4s¹

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Solution

The correct option is C
[Ar] 4s²

The correct electronic configuration for an alkaline earth metals is [Ar] 4s² because they have two electrons in valence shell.

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Similar questions

[A r] 3 d^{10} {4 s}^{1}

is electron shell configuration for:

Sir/Madam

In the structure of copper sulphate(CuSO4.5H2o),4 water molecules are coordinated and 1 is hydrogen bonded. The electronic configuration of Cu is [Ar]4s¹3d¹⁰. When the water molecules are sharing 8 electrons, it becomes 4s2 3d10 4p6 5s1. When cu becomes cu2+ion, the configuration becomes 4s2 3d10 4p5. But these 2 configurations aren't stable. Then why did cuso4.5h2o occurs at a reasonably good amount in nature. Kindly explain in "detail"?

Q. Which one of the following ions has an electronic configuration of

[A r] 3 d^{10}

The electronic configuration of Ti is 1 $s^{2}$ 2 $s^{2}$ 2 $p^{6}$ 3 $s^{2}$ 3 $p^{6}$ 3 $d^{2}$ 4 $s^{2}$ and it represents

M^{3 +}

has electronic configuration as

[A r] 3 d^{10}

, hence it lies in:

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The correct electronic configuration of an alkaline earth metals can be:

The correct option is C [Ar] 4s2 The correct electronic configuration for an alkaline earth metals is [Ar] 4s2 because they have two electrons in valence shell.

The correct option is C
[Ar] 4s²

The correct electronic configuration for an alkaline earth metals is [Ar] 4s² because they have two electrons in valence shell.