The correct electronic configuration of element having mass number 39 and having number of neutrons 20 is ___________.

2,8,8

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2,8,8,1

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2,8,8,2

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2,8,7,2

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Solution

The correct option is B 2,8,8,1
No. of protons = mass number-number of neutrons $= 39 - 20 = 19$ that is equal to number of electrons. K shell will have 2 electrons. L shell will have 8 electrons. M shell will have 8 electrons. N shell will have 1 electron.

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Similar questions

An element A atomic number 7 mass number 14

B electronic configuration 2, 8, 8

C electrons 13, neutrons 14

D Protons 18 neutrons 22

E electronic configuration 2, 8, 8, 1

State (i) valency of each element (ii) which one is a metal (iii) which is a non-metal (iv) which is an inert gas.

_{Z} X^{A}

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An atom has an atomic number of 19 and a mass number of 39. How many electron ,protons and neutrons does it have?

A

2, 8, 13, 2.

l = 0

_{Z} X^{A}

| (A - 2 Z) |

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