wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

The correct electronic configuration of V2+ is:


A

1 2 2 2 3

No worries! We‘ve got your back. Try BYJU‘S free classes today!
B

1 2 2 3 3 3

No worries! We‘ve got your back. Try BYJU‘S free classes today!
C

1 2 2 3 3 4 3

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
D

None of the above

No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is C

1 2 2 3 3 4 3


The order in which the orbitals are filled is as follows:

1s, 2s, 2p, 3s, 3p, 4s, 3d, 4p, 5s, 4d, 5p, 6s, 4f, 5d, 6p, 7s

Atomic number of V = 23

Number of electrons in V2+ = 21

V2+ = 1s2 2s2 2p6 3s2 3p6 4s0 3d3!

Surprised?
See, the thing is: although 4s has a lower energy than 3d, it is the outermost shell. So any electrons to leave would be the ones from this shell first.


flag
Suggest Corrections
thumbs-up
1
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
VSEPR Theory and Dipole Moment
CHEMISTRY
Watch in App
Join BYJU'S Learning Program
CrossIcon