The correct end product (major) of the following reaction is:

2-methoxy propane

No worries! We‘ve got your back. Try BYJU‘S free classes today!

1-methoxy propane

No worries! We‘ve got your back. Try BYJU‘S free classes today!

propan-2-ol

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

propan-1-ol

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is A propan-2-ol
In presence of sunlight, the addition of bromine follows a free radical mechanism.

$C H_{3} - C H_{2} - C H_{3} B r_{2} / h v - --- \to C H_{3} C H B r - C H_{3} + H B r C H_{3} O H - ---- \to C H_{3} C H (O H) - C H_{3}$ (propan-2-ol)

Suggest Corrections

Similar questions

K M n O_{4}

{C S}_{2}

M g B r

1-Methoxy-2-(2-methoxy ethoxy)ethane

Join BYJU'S Learning Program