The correct energy level diagram for $[C o (C N)_{6}]^{3 -}$ is

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Solution

The correct option is D
The given complex is a octahedral complex. In octahedral, the splitting of degenerated d-orbitals takes place as $d_{x^{2} - y^{2}}, d_{z^{2}}$ and $d_{x y}, d_{y z}, d_{x z}$ .

$d_{x y}, d_{y z}, d_{x z} \to t_{2 g}$
$d_{x^{2} - y^{2}}, d_{z^{2}} \to e_{g}$
$t_{2 g}$ represent triply degenerate gerade orbital (orbital with centre of symmetry)
$e_{g}$ represent doubly degenerate gerade orbital.
The metal in complex has the oxidation state of +3. Thus, the configuration of $C o^{+ 3}$ is $d^{6}$ .
Since, cyanide ion is a strong field ligand, electrons gets paired up in complex. Hence, it is a low spin complex where splitting energy is higher than pairing energy. Hence, all six electrons are present in lower $t_{2 g}$ energy level.

Thus, option (b) is correct.

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Similar questions

The colour of the coordination compounds depends on the crystal field splitting. What will be the correct order of absorption of wavelength of light in the visible region, for the complexes, $[C o (N H_{3})_{6}]^{3 +}, [C o (C N)_{6}]^{3 -}, [C o (H_{2} O)_{6}]^{3 +}$
$[C o (N H_{3})_{6}]^{3 +}, [C o (C N)_{6}]^{3 -}, [C o (H_{2} O)_{6}]^{3 +}$
(a) $[C o (C N)_{6}]^{3 -} > [C o (N H_{3})_{6}]^{3 +} > [C o (H_{2} O)_{6}]^{3 +}$
(b) $[C o (N H_{3})_{6}]^{3 +} > [C o (H_{2} O)_{6}]^{3 +} > [C o (N H_{3})_{6}]^{3 +}$
(c) $[C o (H_{2} O)_{6}]^{3 +} > [C o (N H_{3})_{6}]^{3 +} > [C o (C N)_{6}]^{3 -}$
(d) $[C o (C N)_{6}]^{3 -} > [C o (N H_{3})_{6}]^{3 +} > [C o (H_{2} O)_{6}]^{3 +}$

Q. In

[C o (C N)_{6}]^{4 -}

and

[C o (C N)_{6}]^{3 -}

Using crystal field theory, draw energy level diagram. Write electronic configuration of the central metal atom/ion and determine the magnetic moment value in the following:

l. $[C o F_{6}]^{3 -}, [C o (H_{2} O)_{6}]^{2 +}, [C o (C N)_{6}]^{3 -}$

ll. $[F e F_{6}]^{3 -}, [F e (H_{2} O)_{6}]^{2 +}, [F e (C N)_{6}]^{4 -}$

Q. The overall formation constant for the reaction of

6 m o l of -^{C} N i o n s

with Co(II) ions is

10^{20}

. The standard reduction potential for the reaction

[C o (C N)_{6}]^{3 -} + e^{-} \to [C o (C N)_{6}]^{4 -} is - 0.78 V

C o^{3 +} + e^{-} \to C o^{2 +} E^{\circ} = 1.80 V

If the formation constant for

[C o (C N)_{6}]^{3 -} is 10 a

, then the value of a is

Q. 6. which is more stable? [cocn6]3- or [cocn6]2-

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The correct energy level diagram for [Co(CN)6]3− is

The correct energy level diagram for $[C o (C N)_{6}]^{3 -}$ is