The correct formula for specific gravity of a substance is

S G = \frac{Density of substance}{Density of water at 0^{\circ} C}

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S G = \frac{Density of subtance}{Density of water at 4^{\circ} C}

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S G = \frac{Density of water}{Density of substance}

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S G = \frac{Gravity force}{Mass}

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Solution

The correct option is B $S G = \frac{Density of subtance}{Density of water at 4^{\circ} C}$
Specific gravity of a substance is given by,
$S G = \frac{Density of substance}{Density of water at 4^{\circ} C}$
The units of density cancel out in the numerator and denominator. So, $S G$ has no units.

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In making an alloy, a substance of specific gravity $s_{1}$ and mass $m_{1}$ is mixed with another substance of specific gravity $s_{2}$ and mass $m_{2}$ ; then the specific gravity of the alloy is

Q. If

M_{1}

gm of a substance with specific gravity

S_{1}

is mixed with

M_{2}

gm of a substance with specific gravity

S_{2}

and then the substances are used to make an alloy. What will be the specific gravity of the alloy.

Q. Assertion :Specific gravity is dimensionless. Reason: Specific gravity is density of a substance measured w.r.t. density of water at

4^{\circ} C

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Density

Standard XII Physics

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The correct formula for specific gravity of a substance is

The correct option is B SG=Density of subtanceDensity of water at 4∘CSpecific gravity of a substance is given by, SG=Density of substanceDensity of water at 4∘C The units of density cancel out in the numerator and denominator. So, SG has no units.

The correct option is B $S G = \frac{Density of subtance}{Density of water at 4^{\circ} C}$
Specific gravity of a substance is given by,
$S G = \frac{Density of substance}{Density of water at 4^{\circ} C}$
The units of density cancel out in the numerator and denominator. So, $S G$ has no units.