The correct formula of rust is

F e_{2} O_{3}

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F e_{3} O_{4}

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F e_{2} O_{3} . x H_{2} O

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F e_{3} O_{4} . x H_{2} O

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Solution

The correct option is C $F e_{2} O_{3} . x H_{2} O$
$2 F e + \frac{3}{2} O_{2} + x H_{2} O      F r o m m o i s t a i r \to F e_{2} O_{3} . x H_{2} O H y d r a t e d f e r r i c o x i d e (r u s t)$

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Similar questions

F e_{2} O_{3}

{F e}_{2} O_{3} . x H_{2} O

F e (s) \to F e^{2 +} (a q) + 2 e^{-}

O_{2} (g) + 4 H^{\oplus} (a q) + 4 e^{-} \to 2 H_{2} O (l)

4 F e^{2 +} (a q) + O_{2} (g) + 4 H_{2} O (l) \to 2 F e_{2} O_{3} (s) + 8 H^{\oplus}

F e_{2} O_{3} (a q) + x H_{2} O (l) \to F e_{2} O_{3} . x H_{2} O

N a C l

C O_{2}

Chemical formula of rust.

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