The correct increasing order of adsorption of the following gases on the same mass of charcoal at the same temperature and pressure is:
1. $H_{2}$
2. $S O_{2}$
3. $C H_{4}$

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Solution

Increasing order of adsorption of the following gases on the same mass of charcoal at the same $T$ and $P$ is $H_{2} < C H_{4} < S O_{2}$ .
Here, lesser the critical temperature of gases lesser will be the extent of adsorption.
Critical temperature:- The temperature at which gases is liquified is called critical temperature.
Critical temperature order (in $K$ ) $H_{2} < C H_{4} < S O_{2}$ .

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C H_{4}

S O_{2}

Gas	$H_{2}$	$C H_{4}$	$C O_{2}$	$S O_{2}$
Critical Temperature $(K)$	$33$	$190$	$304$	$630$

Gas	$C O_{2}$	$S O_{2}$	$C H_{4}$	$H_{2}$
Critical temp./K	304	630	190	33

H_{2}, C H_{4}, C O_{2}

N H_{3}

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