The correct option is C hydrogen hexachloridoplatinate(IV)
IUPAC name of the complex is hydrogen hexachloridoplatinate(IV). Here in the anion [PtCl6]−2 Pt is in +4 oxidation state which is written in the parenthisis in roman. There are six chlorine atoms present so the hexachloridoplatinate name is justified (As Pt is in the anion counterpart). So option (a) is correct.