Question

The correct IUPAC name of the compound is

• A. $\text{4-Bromo-1-chloro-2-fluoroiodomethylbutene}$
• B. $\text{4-Bromo-2-chloromethyl-1-fluoro-1-iodobut-l-ene}$
• C. $\text{2-(2-Bromoethyl)-3-chloro-l-fluoro-1-iodoprop-1-ene}$
• D. $\text{1-Bromo-3-chloromethyl-4-fluoro-4-iodobut-1-ene}$

Answer 1

The correct option is B $\text{4-Bromo-2-chloromethyl-1-fluoro-1-iodobut-l-ene}$

Lower number to carbon having double bond as all other halogens are substituents.
parent chain is of 4 carbon
functional group is alkene and suffix used for alkene is -ene.
Hence correct IUPAC name is $\text{4-Bromo-2-chloromethyl-1-fluoro-1-iodobut-l-ene}$