Question

The correct IUPAC name of the given compound is
$I-\underset{\underset{F}{|}}{C}=\underset{\underset{Cl}{|}}{C}-C\equiv C-OC{H}_3$

• A. $\text{3-Chloro-1-fluoro-1-iodo-4-methoxybut-1-en-3-yne}$
• B. $\text{4-Methoxy-2-chloro-1-fluoro-1-en-2-yne}$
• C. $\text{3-Chloro-4-fluoro-4-iodo-1-methoxybut-1-en-2-yne}$
• D. $\text{2-Chloro-1-fluoro-1-iodo-4-methoxybut-1-en-3-yne}$

Answer 1

The correct option is D $\text{2-Chloro-1-fluoro-1-iodo-4-methoxybut-1-en-3-yne}$

The correct numbering to the longest chain is given by $I-\underset{\underset{F}{|}}{\stackrel{1}{C}}=\underset{\underset{Cl}{|}}{\stackrel{2}{C}}-\stackrel{3}{C}\equiv \stackrel{4}{C}-OC{H}_3$
parent chain is of four carbon thus root word is butane
-X (F, Cl, Br, I), -OR do not have any priority order and considered as alkyl substituents while numbering.
the correct IUPAC name is $\text{2-Chloro-1-fluoro-1-iodo-4-methoxybut-1-en-3-yne}$