The correct Lewis acid order for boron halides is:

B B r_{3} > B C l_{3} > B I_{3} > B F_{3}

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B I_{3} > B F_{3} > B B r_{3} > B C l_{3}

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B F_{3} > B C l_{3} > B B r_{3} > B I_{3}

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B I_{3} > B B r_{3} > B C l_{3} > B F_{3}

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Solution

The correct option is D $B I_{3} > B B r_{3} > B C l_{3} > B F_{3}$
(i) On the basis of back bonding, smaller be the halide atom, more effective be the back bonding and show less tendency to accept a pair of electrons.
(ii) Size of halides increase down the group, hence the ability of back bonding decreases making the molecule more acidic.
Hence, correct order of Lewis acid for boron-halides is $B l_{3} > B B r_{3} > B C l_{3} > B F_{3}$ .

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The correct order of Lewis acidity of $B X_{3}$ molecule is

B F_{3} < B C l_{3} < B B r_{3} < B I_{3}

B F_{3}, B C l_{3}, B B r_{3}, B I_{3}

B F_{3}

B C l_{3}

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B B r_{3}, B C l_{3}

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