The correct mass ratio of $C, N, H, O$ present in urea is

3 : 7 : 1 : 8

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3 : 7 : 1 : 4

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3 : 7 : 2 : 8

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3 : 7 : 2 : 4

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Solution

The correct option is B $3 : 7 : 1 : 4$
Urea is $N H_{2} - C O - N H_{2} .$ The correct mass ratio of C,N,H,O present in urea is $12 : 28 : 4 : 16$ that is $3 : 7 : 1 : 4$ .

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Similar questions

_{3} L i^{7} +_{1} H^{2} \to_{4} B e^{8} +_{o} n^{1} + Q

Mass of

_{3} L i^{7} =

7.01823 a m u

Mass of

_{1} H^{2} =

2.01474 a m u

Mass of

_{4} B e^{8} =

8.00785 a m u

Mass of

_{o} n^{1} =

1.00899 a m u

Then, the value of Q is

Q. Balance the following equation by ion electron method:

C r_{2} O_{7}^{2 -} + C_{2} H_{4} O + H^{+} \to 2 C r^{3 +} + C_{2} H_{4} O_{2} + H_{2} O

$N_{2} O_{4}$ is dissociated to 33% and 50% at total pressure $P_{1}$ and $P_{2}$ atm respectively. The ratio of $\frac{P_{1}}{P_{2}}$ is:

Q. Find the value of:

(1) 3⁶
(2) 6³
(3) 2⁶
(4) 1⁸
(5) 5⁴
(6) 4³
(7) 10⁵
(8) 10⁷
(9) 7⁴
(10) 8²

If
A = {1, 2, 3, 4}

B = {3, 4, 5, 6, 7}

C = {6, 7, 8, 9}

D = {7, 8, 9, 10}

$\begin{matrix} C o l u m n A & C o l u m n B 1. A \cup B & a . {3, 4, 6, 7} 2. A \cap B & b . \emptyset 3. (B \cap C) \cup D & c . {3, 4} 4. B \cup C \cup D & d . {3, 4, 5, 6, 7, 8, 9, 10} 5. (A \cap B) \cap (B \cup C) & e . {1, 2, 3, 4, 5, 6, 7} f . {6, 7, 8, 9, 10} g . {7} \end{matrix}$

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The correct mass ratio of C,N,H,O present in urea is

The correct option is B 3:7:1:4Urea is NH2−CO−NH2. The correct mass ratio of C,N,H,OC,N,H,O present in urea is 12:28:4:16 that is 3:7:1:4.

The correct mass ratio of $C, N, H, O$ present in urea is

The correct option is B $3 : 7 : 1 : 4$
Urea is $N H_{2} - C O - N H_{2} .$ The correct mass ratio of C,N,H,O present in urea is $12 : 28 : 4 : 16$ that is $3 : 7 : 1 : 4$ .