The correct match between Item I and Item II is :
Item I Item II
(A) Ester test (P) Tyr
(B) Carbylamine test (Q) Asp
(C) Phthalein dye test (R) Ser
(S) Lys

(A) \to (Q); (B) \to (S); (C) \to (P)

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(A) \to (R); (B) \to (Q); (C) \to (P)

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(A) \to (Q); (B) \to (S); (C) \to (R)

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(A) \to (R); (B) \to (S); (C) \to (Q)

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Solution

The correct option is B $(A) \to (Q); (B) \to (S); (C) \to (P)$
(A) Ester test (Q) Aspartic acid [Acidic amino acid]

(B) Carbylamine (S) Lysine [ $N H_{2}$ group present]

(C) Phthalein dye (P) Tyrosine [Phenolic group present]

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\begin{matrix} C o l u m n - I & C o l u m n - I I (a) & H y d r o g e n p e r o x i d e i s u s e d a s a & (p) & Z e o l i t e (b) & U s e d i n C a l g o n m e t h o d & (q) & P e r h y d r o l (c) & P e r m a n e n t h a r d n e s s o f w a t e r i s r e m o v e d b y & (r) & H e x a m e t a p h o s p h a t e (s) & P r o p e l l a n t \end{matrix}

Column I

Column II

\begin{matrix} C o l u m n I & C o l u m n I I (T y p e o f △ A B C) a. cot \frac{A}{2} = \frac{b + c}{a} & p. always right angled b. a tan A + b tan B = (a + b) tan \frac{A + B}{2} & q. always isosceles c. a cos A = b cos B & r. may be right angled d. cos A = \frac{sin B}{2 sin C} & s. may be right angled isosceles \end{matrix}

s p^{3}

B F_{3}

s p^{2}

Item-I (drug)	Item-II (test)
(A)	Chloroxylenol	(P)	Carbylamine test
(B)	Norethindrone	(Q)	Sodium hydrogen carbonate test
(C)	Sulphapyridine	(R)	Ferric chloride test
(D)	Penicillin	(S)	Bayer's test

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