Question

The correct name of $\left[Pt{\left({NH}_3\right)}_4{Cl}_2\right]\left[Pt{Cl}_4\right]$ is:

• A. Tetraammine dichloro platinum (IV) tetrachloro platinate(II)
• B. Dicholoro tetra mmine platinum (IV) tetrachloro platinate (II)
• C. Tetrachloro platinum (II) tetraammine platinate (IV)
• D. Tetrachloro platinum (II) dichloro tetraamine platinate (IV)

Answer 1

The correct option is A Tetraammine dichloro platinum (IV) tetrachloro platinate(II)

Tetraaminedichloro platinum (IV) tetrachloroplatinate(II)

First, we have to write the cationic part, of the coordinate compound

Here, the ligands are Amine and Chloride. Since there are $4$ amine groups we’ll name it as tetramine and $2$ chloride groups will be named as dichloro. Also, we have platinum metal as the central metal atom in a cation, and it’s oxidation state is $+4$.

Now for the other (anionic part):

Here the ligand is chloride. Since there are $4$ chlorides so we’ll call it tetrachloride. We have the central metal atom as platinum again, but since it is in the anionic coordination sphere.