You visited us 1 times! Enjoying our articles? Unlock Full Access!

Faraday's First Law

The correct N...

Question

The correct Nernst equation for the given cell $P t_{(s)} | B r_{2 (l)} | B r^{-} (M) | | H^{+} (M) | H_{2 (g)} (1 b a r) | P t_{(s)}$ is?

E_{c e l l} = E_{c e l l}^{o} - \frac{0.0591}{2} l o g \frac{1}{[H^{+}]^{2} [B r^{-}]^{2}}

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

E_{c e l l} = E_{c e l l}^{o} - \frac{0.0591}{2} l o g \frac{[H^{+}]^{2} [B r^{-}]^{2}}{[B r_{2 (l)}] [H_{2}]}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

E_{c e l l} = E_{c e l l}^{o} - \frac{0.0591}{2} l o g \frac{[H^{+}]^{2} [H_{2}]}{[B r_{2 (l)}] [B r^{-}]^{2}}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

E_{c e l l} = E_{c e l l}^{o} - \frac{0.0591}{2} l o g \frac{[B r_{2 (l)}] [B r^{-}]^{2}}{[H^{+}]^{2} [H_{2}]}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is A $E_{c e l l} = E_{c e l l}^{o} - \frac{0.0591}{2} l o g \frac{1}{[H^{+}]^{2} [B r^{-}]^{2}}$
Nernst equation is,
$E_{c e l l} = E_{c e l l}^{0} - \frac{0.0591}{n} l o g Q$

Reactions involved are,
At anode:
$2 B r^{-} (1 M) \to B r_{2} (l) + 2 e^{-}$
At cathode:
$2 H^{+} (1 M) + 2 e^{-} \to H_{2} (1 b a r)$

Net reaction is:
$2 B r^{-} (1 M) + 2 H^{+} (1 M) \to B r_{2} (l) + H_{2} (1 b a r)$

Nernst equation is,
$E_{c e l l} = E_{c e l l}^{0} - \frac{0.0591}{n} l o g Q$
Here,

Nernst equation for the given cell,

$E_{c e l l} = E_{c e l l}^{0} - \frac{0.0591}{n} l o g \frac{1}{[B r^{-}]^{2}] [H^{+}]^{2}}$

Suggest Corrections

Similar questions

298 K

M g (s) | M g^{+ 2} (0.001 M) ∥ C u^{+ 2} (0.0001 M) | C u (s)

F e (s) | F e^{+ 2} (0.001 M) ∥ H^{+} (1 M) | H_{2} (g) (1 b a r) | P t (s)

S n (s) | S n^{2 +} (0.050 M) ∥ H^{+} (0.020 M) | H_{2} (g) (1 b a r) | P t (s)

P t (s) | B r_{2} (l) | B r^{-} (0.010 M) ∥ H^{+} (0.030 M) | H_{2} (g) (1 b a r) | P t (s)

P b (s) + H g_{2} S O_{4} (s) ⇌ P b S O_{4} (s) + 2 H g (l);

E_{c e l l}^{o} = 0.92 V

K_{s p} (P b S O_{4}) = 2 \times 10^{- 8}, K_{s p} (H g_{2} S O_{4}) = 1 \times 10^{- 6}

E_{c e l l}

\sqrt{2} = 1.4, l o g 0.14 = - 0.85

E_{c e l l} = 0.2364 V

P t, (H_{2}) (1 a t m) | H^{\oplus} (x M) | | H^{\oplus} (1 M) (1 a t m) | P t, (H_{2})

298 K

C u (s) | C u^{2 +} (1.0 M) | | A g^{+} (1.0 M) | A g (s)

E_{c e l l}^{o} = 0.46 V

Z n (s) | Z n^{2 +} (1.0 M) | | C u^{2 +} (1.0 M) | C u (s)

E_{c e l l}^{o} = 1.10 V

E_{c e l l}

298 K

Z n (s) | Z n^{2 +} (0.1 M) | | A g^{+} (1. 0 M) | A g (s)

- 0.4

- 0.74

[C d^{2 +}] = 0.1

[C r^{3 +}] = 0.01

E_{c e l l}

E_{c e l l}^{o}

Join BYJU'S Learning Program