The correct option is C A={x:x2−3x+2=0} and B={x,x∈N and |x|≤2}, then they are equal sets.
There is only one even prime number 2, so set of even prime numbers greater than 2 is a null set
The collection of good soccer players is not well-defined, because the criterion for determining a soccer as good may vary from person to person, therefore it is not a set.
A={x:x2−3x+2=0}
x2−3x+2=0
⇒(x−2)(x−1)=0
⇒x=1,2
⇒A={1,2}
B={x,x∈N and |x|≤2}
|x|≤2
⇒x∈[−2,2]
As x∈N
⇒B={1,2}
So, A and B are equal sets.
Factors of 8 are {1,2,4,8}
Factors of 10 are {1,2,5,10}
They are not equal sets.