The correct order according to acidic nature is:

{C H}_{3} O H < {C H}_{3} S H < {C H}_{3} {N H}_{2}

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{C H}_{3} {N H}_{2} < {C H}_{3} O H < {C H}_{3} S H

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{C H}_{3} S H < {C H}_{3} O H < {C H}_{3} {N H}_{2}

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none of these

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Solution

The correct option is B ${C H}_{3} {N H}_{2} < {C H}_{3} O H < {C H}_{3} S H$
The correct option is $B$ .
The correct order of acidity is
$C H_{3} N H_{2} < C H_{3} O H < C H_{3} S H$
$C H_{3} S^{-}$ is more stable than $C H_{3} O^{-}$ because sulphur has greater size than oxygen onion on sulphur is more stable.

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