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Question

The correct order for the wavelength of absorption in the visible resion is :

A
[Ni(NO2)6]4<[Ni(NH3)6]2+<[Ni(H2O)6]2+
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B
[Ni(NO2)6]4<[Ni(H2O)6]2+<[Ni(NH3)6]2+
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C
[Ni(H2O)6]2+<[Ni(NH3)6]2+<[Ni(NO2)6]4
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D
[Ni(NH3)6]2+<[Ni(H2O)6]2+<[Ni(NO2)6]4
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Solution

The correct option is A [Ni(NO2)6]4<[Ni(NH3)6]2+<[Ni(H2O)6]2+
Option (A) is correct.
The correct order for the wavelength of absorption in the visible region is [Ni(NO2)6]4<[Ni(NH3)6]2+<[Ni(H2O)6]2+.
The central metal ion in all the three complexes is the same.Therefore, absorption in the visible region depends on the ligands.The order in which the CFSE values of the ligands increases in the spectrochemical series is as follows :
H2O<NH3<NO2

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