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Bond Order by MOT

The correct o...

Question

The correct order in which the $O - O$ bond length increases in the following is:

H_{2} O_{2} < O_{2} < O_{3}

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O_{3} < H_{2} O_{2} < O_{2}

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O_{2} < O_{3} < H_{2} O_{2}

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O_{2} < H_{2} O_{2} < O_{3}

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Solution

The correct option is C $O_{2} < O_{3} < H_{2} O_{2}$
The bond length decreases with the increase of bond order which is the multiplicity of the bond.
If BO is 1 its a single bond; 2 for double bond and 3 for the triple bond.
$H_{2} O_{2}$ has all single bond with bond length $1.41 ˚ A$
$O_{2}$ has a double bond with bond length $1.33 ˚ A$ .
$O_{3}$ has a partial double bond due to the resonance of lone pairs of electrons thus if we arrange the above molecules a/c to their bond length it would be -
$H_{2} O_{2} > O_{3} > O_{2}$

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